One door — three sides of the frame: how many DK-001 profiles of 2400 mm to order

There is one DK-001 profile 2400 mm long in the cart. The price is clear, the profile is selected, and the color of the future door is already approved. It seems that the main task is solved. But a door frame without a bottom threshold has not one side, but three: two vertical posts and a top crossbar. One profile can provide one long post, but it is impossible to assemble the entire frame around a standard interior door leaf from it.

For a door about 2000 or 2100 mm high, each vertical side requires almost a whole DK-001. After cutting, short pieces remain from two profiles — roughly 300–400 mm in a simplified calculation. Such remnants cannot produce a solid top crossbar of 600, 700, 800, or 900 mm width. Therefore, for one standard three-sided frame, the calculation usually starts with three DK-001 profiles of 2400 mm: two go to the jambs, the third to the top piece.

The word "usually" is key here. The exact quantity cannot be determined solely by the door leaf width. You need the actual jamb lengths, the top crossbar size, joint construction, installation gaps, element thickness, opening width, presence of a bottom threshold, and a technological allowance for cutting. A frame for an 800 × 2000 mm leaf does not have to consist of two pieces exactly 2000 mm and one piece exactly 800 mm. That is just a clear scheme for an initial estimate.

The door frame profile DK-001 has a length of 2400 mm and a cross-section of 100 × 42 mm. The base is made of birch plywood 18 mm thick, and the front part is formed by two glued layers of MDF, each 12 mm. The profile includes a groove 3.4 mm wide for a seal. The model is intended for interior doors, designed for subsequent enamel painting, and is made to order.

Such a construction requires an accurate bill of materials. The buyer needs to count not abstract meters, but specific solid parts: the left jamb, the right jamb, the top crossbar, and, if the project includes a closed frame, the bottom element. Only after that can you Buy door frame profile DK-001 in a quantity that truly corresponds to one or several doors.

The main calculation principle sounds simple:

first, create a cutting map for each solid part, then count profiles of 2400 mm; dividing the total linear meters by 2400 without a cutting map gives an erroneous result.

Door Frame Profile DK-001

from 53.40 $

Go to Catalog

Short answer: how many DK-001 are needed for one interior door

For a three-sided door frame around a leaf 2000 or 2100 mm high and 600–900 mm wide, three DK-001 profiles of 2400 mm are preliminarily allocated:

• one profile — for the left vertical jamb;

• the second — on the right vertical post;

• the third — on the top crossbar.

If the box includes a bottom element, one third profile in many calculation scenarios can provide both horizontal parts, since their total length is usually less than 2400 mm. But the final cutting depends on exact dimensions, saw kerf, and technological allowance.

Two profiles for a standard door about 2000–2100 mm high typically do not yield three full sides. Each vertical post takes up almost the entire length of a separate blank. The remnants end up shorter than the top crossbar.

Three profiles are not a ready-made universal specification, but a reliable starting point for a typical three-sided scheme. After measuring, you need to confirm the length of each blank and the possibility of using the remainder of the third profile for other parts.

Watch video ...

Why is a door frame calculated by parts, not by meters

Let's imagine a conditional door 800 mm wide and 2000 mm high. The simplified total length of the three sides is:

2000 + 2000 + 800 = 4800 mm.

If you divide 4800 mm by the length of DK-001, you get:

4800 ÷ 2400 = 2.

On paper, it comes out to exactly two profiles. In real cutting, this number doesn't work.

From the first DK-001, a post about 2000 mm long is cut. About 400 mm remains, excluding the cut and allowance. From the second, you get the second post and another remainder of about 400 mm. Two separate 400 mm pieces cannot be turned into one solid top crossbar about 800 mm long.

The mathematical sum of material matched, but the geometry of the parts did not. A third profile is required for the frame.

That's why the expression "how many meters of door frame are needed" is only convenient at the first stage. It shows the total volume but does not determine the number of product items. The next step is a cutting map, where each post and crossbar is placed within a specific 2400 mm segment.

Our factory also produces:

Wooden Capital KL-011

from 178.94 $

Ton HL-058-2M furniture handle

from 38.25 $

Wooden decoration N-332

from 48.30 $

Wooden decor N-041

from 16.27 $

View Full Product Catalog

The total length answers only one question

The formula for the total length without the bottom element looks like this:

Ltotal = 2 × Hpost + Ltop rail + technological allowance.

It shows how much material is needed in total. But other questions remain:

• can two parts be cut from one profile;

• which parts must be solid;

• what length will remain after each post;

• is the remainder suitable for the top rail;

• how much material will go to the cut;

• is an allowance for end trimming required;

• are joints allowed;

• is there a bottom element;

• Is it possible to combine the cutting of several identical doors?

To answer, you need not just one formula, but a layout scheme for placing parts.

A solid part is more important than a beautiful leftover.

Two leftovers of 400 mm arithmetically give 800 mm. But the top crossbar does not turn into a solid part by simply adding numbers.

A joint in the visible or structural part of the frame cannot be considered acceptable without a separate design solution. The article should not suggest joining short leftovers just to save money. For a standard parts list, posts and crossbars are considered solid.

Leftovers are kept for test painting, tool setup, groove checking, making a joint sample, or another confirmed task. But in the door frame calculation, they should not automatically replace a full-size element.

The saw kerf also takes away length.

Even when the sum of parts equals 2400 mm, this does not mean they are guaranteed to fit into one DK-001. The tool removes part of the material along the cut line. Additionally, an allowance for precise trimming may be needed.

For example, three horizontal parts of 800 mm each give exactly 2400 mm. Without the saw kerf, the arithmetic looks flawless. In a working card, such cutting cannot be considered guaranteed: there will be cuts between the three parts, and the edge of the workpiece may require alignment.

Therefore, cutting 'to zero' is not used as a safe basis for an order. A technological allowance is needed, the size of which is determined by the production or the craftsman.

Three sides of a regular box: what exactly is cut from DK-001

A box without a bottom threshold consists of two vertical posts and a top crossbar. Each part has its own task and its own size.

Left vertical post

The post runs from the bottom mark of the box to the top joint. Its length is not always equal to the height of the panel. The size is affected by the box construction, gaps, joining method, and the design floor mark.

With a panel height of 2000 mm, you cannot automatically specify a post of exactly 2000 mm. This figure is only suitable for a preliminary illustration. The working length is taken from the drawing.

Since the post is close to two meters, it occupies a separate DK-001 with a length of 2400 mm.

Right vertical post

The second post usually has a comparable length, but it cannot be replaced with the remainder from the first one. Another solid blank is required for it.

If the posts differ in construction, for example due to threshold features or abutment, each one is still listed as a separate line in the cutting map.

Top crossbar

The horizontal part connects the uprights. Its size depends not only on the nominal width of the panel. You need to account for the internal geometry of the frame, gaps, and the connection method.

It is the top crossbar that usually causes the third DK-001. The remnants after the uprights are too short, and the part itself must remain solid.

Bottom element

Not every interior door frame has a bottom crossbar. If the project includes a threshold or a closed four-sided structure, another horizontal part appears.

For a door width of 600–900 mm, the top and bottom crossbars in many preliminary schemes fit into one 2400 mm profile. For example, two parts of 900 mm each give 1800 mm, leaving room for cutting and allowance. But the actual dimensions need to be confirmed.

Can a frame be assembled from two DK-001

For a typical panel height of 2000 or 2100 mm and width of 600–900 mm — usually no.

Two profiles give two solid vertical uprights. After that, short offcuts remain. Their length is insufficient for a solid top crossbar.

Conditional door 600 × 2000 mm

Preliminary scheme:

• left upright — about 2000 mm;

• right post — about 2000 mm;

• top crossbar — about 600 mm.

From two DK-001 after the posts, approximately 400 mm will remain from each. Neither remainder provides a 600 mm crossbar.

Conventional door 800 × 2000 mm

After two posts, the same approximate 400 mm pieces remain. For a crossbar of about 800 mm, a third profile is needed.

Remainders cannot be joined if the project requires a single solid piece.

Conventional door 900 × 2100 mm

After each post, about 300 mm remains. The top crossbar needs to be significantly longer. A third DK-001 is mandatory in the preliminary list.

When two profiles could theoretically suffice

For this, the post and the horizontal piece must fit within a single profile:

Hстойки + Lперекладины + пропил + запас ≤ 2400 мм.

With a post of about 2000 mm, less than 400 mm remains for the crossbar. With a post of about 2100 mm, less than 300 mm remains. For doors 600–900 mm wide, the condition is not met.

If the project has a non-standard small height or narrow structure, the calculation is performed anew. But such an exceptional case cannot be transferred to a regular interior door.

Calculation DK-001 for a panel 2000 mm high

The following examples show the logic, not replace a working drawing. For clarity, conditional posts of 2000 mm and a horizontal part equal to the nominal width of the panel are assumed. Mounting gaps and connections are not calculated in the example.

Door 600 mm wide

Total arithmetic length:

2000 × 2 + 600 = 4600 mm.

By the sum, it seems that two profiles of 2400 mm are sufficient, since their total length is 4800 mm.

The cutting map shows otherwise:

• profile No. 1: post 2000 mm, remainder about 400 mm;

• profile No. 2: post 2000 mm, remainder about 400 mm;

• profile No. 3: crossbar about 600 mm.

Preliminary quantity — 3 DK-001.

Door width 700 mm

Total length:

2000 × 2 + 700 = 4700 mm.

Two profiles give 4800 mm, but a whole crossbar of 700 mm does not fit into the remainders.

Preliminary quantity — 3 DK-001.

Door width 800 mm

Total length:

2000 × 2 + 800 = 4800 mm.

This is the most illustrative example of a division error: the total length is exactly equal to two profiles, but two posts take 2000 mm each, and a crossbar of 800 mm cannot be obtained from two parts of 400 mm each.

Preliminary quantity — 3 DK-001.

Door 900 mm wide

Total length:

2000 × 2 + 900 = 4900 mm.

Even the total already exceeds 4800 mm. A third profile is needed both by length and by cutting layout.

Preliminary quantity — 3 DK-001.

The table shows why the total is not determined by a single division. Even in the 800 × 2000 mm row, where the sum is 4800 mm, a third profile is required due to the need to obtain three whole pieces.

Panel height 2100 mm: the remnants become even shorter

With a conditional post length of 2100 mm, about 300 mm remains from one DK-001 before accounting for the cut and trimming.

Two posts give two short remnants, but neither is suitable for a crossbar with a width of 600–900 mm.

Door 600 × 2100 mm

Simplified total length:

2100 × 2 + 600 = 4800 mm.

By the total sum, again two profiles are obtained. But the cutting looks like this:

• first profile: upright 2100 mm, remainder about 300 mm;

• second profile: upright 2100 mm, remainder about 300 mm;

• third profile: crossbar about 600 mm.

Preliminary — 3 DK-001.

Door 700 × 2100 mm

Total length — 4900 mm. Three profiles are needed without additional proof, and the cutting map confirms the decision.

Door 800 × 2100 mm

Total length — 5000 mm. The uprights occupy two separate profiles, the crossbar is cut from the third.

Door 900 × 2100 mm

Total length — 5100 mm. The preliminary order also includes three DK-001.

Height 2100 mm reinforces the main conclusion: short remnants after the posts cannot be considered a finished top part.

Box with bottom element: will a fourth profile be needed

A closed box has four sides:

• two vertical posts;

• top crossbar;

• bottom crossbar or threshold element.

At first glance, it seems that four sides correspond to four profiles. For DK-001, this is not always the case. Two horizontal parts with a width of 600–900 mm are usually shorter than 2400 mm in total.

A conditional example for a door with a width of 800 mm:

• top part — about 800 mm;

• bottom part — about 800 mm;

• in total — about 1600 mm.

Both blanks can be considered for cutting from the third DK-001. After them, there is room for the saw cut and technological allowance. Therefore, the preliminary quantity for one four-sided frame may still be three profiles.

But there are limitations:

• actual horizontal dimensions may differ from the width of the door leaf;

• the design of the bottom element may be different;

• end joints require an allowance;

• the project may provide for special processing;

• additional parts may be cut from the third profile;

• the cutting plan must be approved before production.

You cannot write in the invoice "three profiles for any box with a threshold." The correct entry contains four lengths and a map of their placement.

Conditional table for one box with a bottom element

The table does not account for the actual joint construction. It shows why the fourth side does not necessarily mean a fourth line item.

Calculation formula DK-001 for one door

For a three-sided frame:

Ltotal = 2 × H + W + Z,

Where:

• H — length of one vertical post;

• W — length of the top crossbar;

• Z — total technological allowance.

For a four-sided frame:

Ltotal = 2 × H + Wtop + Wbottom + Z.

But after calculating Ltotal, you cannot immediately apply:

N = rounding up Ltotal ÷ 2400.

This formula gives only the theoretical quantity based on the total material. The working number is determined as follows:

1. List each whole piece.

2. Place the pieces inside profiles with a length of 2400 mm.

3. Add the cut and allowance.

4. Exclude prohibited joints.

5. Check the leftovers.

6. Calculate the actual blanks.

It is more convenient to write:

Nactual = the number of 2400 mm profiles required according to the cutting map of whole pieces.

This is not a neat algebraic formula, but it reflects the real purchase.

Calculation for two identical doors

Ordering several identical doors allows using the third profile more efficiently. Vertical posts still take individual blanks, while top rails can be grouped.

For two doors, you need:

• four vertical posts;

• two top rails;

• with a closed box — two more bottom pieces.

With posts about 2000–2100 mm long, four DK-001 are allocated for four verticals.

Two horizontal pieces 600–900 mm wide fit into one 2400 mm profile with noticeable leftover:

• 2 × 600 = 1200 mm;

• 2 × 700 = 1400 mm;

• 2 × 800 = 1600 mm;

• 2 × 900 = 1800 mm.

Preliminary calculation for two three-sided boxes — 5 DK-001 profiles.

Why not six

If each door is counted separately, it would be 3 + 3 = 6. But the third profile of the first door after the crossbar has a large remainder. With joint cutting from one blank, two horizontal parts can be obtained.

This is where a combined order provides savings. But it only appears after creating a combined cutting map, not from arbitrarily reducing the quantity.

Two doors with bottom elements

Four horizontal parts will be needed. Their total length ranges from 2400 to 3600 mm in conditional scenarios.

Cutting exactly four parts of 600 mm from one profile gives 2400 mm without accounting for the cut and allowance. This option cannot be considered guaranteed. For a safe preliminary list, two profiles are allocated for four horizontal parts.

Total:

• four profiles for uprights;

• two profiles for the top and bottom parts;

• preliminarily 6 DK-001.

Calculation for three identical doors

For three doors without a bottom element, you need:

• six vertical posts;

• three top crossbars.

The verticals require six separate profiles.

The horizontals are distributed across the width.

Width about 600 mm

Three parts:

600 × 3 = 1800 mm.

They are pre-placed in one DK-001 with a margin. Total quantity:

6 + 1 = 7 profiles.

Width about 700 mm

Three parts:

700 × 3 = 2100 mm.

Space remains for cutting and allowance, but the specific margin is checked. Preliminary:

7 profiles.

Width about 800 mm

Three parts give exactly 2400 mm. Due to cutting and the need for end trimming, such a layout cannot be considered guaranteed. For a safe preliminary list, the horizontals are distributed across two profiles.

Total:

6 + 2 = 8 profiles.

Width about 900 mm

Three crossbars give 2700 mm, so two profiles are required.

Total:

8 DK-001.

The table is based on conditional horizontal dimensions. The actual result changes after refining the box construction.

Calculation for five identical doors

Five doors without a bottom element require ten vertical posts. With a length of about 2000–2100 mm, each post occupies a separate DK-001.

10 profiles are pre-laid on the vertical parts.

Then five crossbars are counted.

Width about 600 mm

Three conditional parts of 600 mm each are safely placed in one profile:

600 × 3 = 1800 mm.

Two DK-001 will be needed for five crossbars.

Total preliminary order:

10 + 2 = 12 profiles.

Width about 700 mm

Three parts give 2100 mm. The remaining two are cut from the second profile.

Total:

12 DK-001.

Width about 800 mm

Two parts give 1600 mm. Three parts exactly fill 2400 mm without reserve, so three profiles are pre-laid for five crossbars.

Total:

10 + 3 = 13 DK-001.

Width about 900 mm

Two crossbars with a total length of 1800 mm are placed in one profile. Three profiles are needed for five parts.

Total:

13 DK-001.

Ordering five doors for three profiles per each would give 15 DK-001. The overall cutting plan reduces the preliminary quantity to 12–13, because horizontal elements are grouped.

Several doors with bottom rails

With a closed frame, the number of horizontal parts doubles. For five doors, ten horizontal blanks will be needed.

Conditional scheme for safe preliminary cutting:

• parts around 600–700 mm — no more than three per one DK-001;

• parts around 800–900 mm — no more than two per one DK-001.

This is not a production technology standard, but a conservative calculation model that does not attempt to fill the profile exactly to 2400 mm.

For one door, two horizontals fit into the third profile. For multiple doors, the savings depend on their actual length and cutting.

Residues of 300–400 mm: discard or account for

After cutting posts about 2000–2100 mm high, pieces approximately 300–400 mm long remain before accounting for the saw cut. In a large batch, there are many such residues. The buyer naturally asks: can the order be reduced by using them?

For the top rail of a standard door 600–900 mm wide — no. Each residue is shorter than the required solid piece.

But residues can be useful for auxiliary tasks:

• test application of primer and enamel;

• checking the shade;

• saw settings;

• testing the quality of end cutting;

• making a sample of a corner joint;

• checking the fit of the seal in the 3.4 mm groove;

• matching the surface with the casing;

• of the demonstration fragment for the customer.

This application does not mean that all remnants must necessarily be stored. Before production, they decide which samples are actually needed.

Do not put remnants into "virtual meters"

In the estimate, a line sometimes appears: "After ten posts, four meters of material will remain, so the remaining elements can be made from them." This phrase is dangerous. The four meters are distributed among ten short segments, not collected in a single solid workpiece.

For each remnant, the actual length is recorded. Only then is it checked whether a solid part of a smaller size exists in the project.

Joining remnants

Connecting short parts into a post or crossbar should not become a way to save money without design confirmation. The joint affects the geometry, painting, and operation of the box.

In the standard commercial list DK-001, posts and top parts are considered solid.

What measurements are needed before ordering DK-001

Nominal dimensions of the door leaf are just the beginning. To calculate the profile, the craftsman must obtain the parameters of the opening, the leaf, and the future frame.

Blade height

It is recorded separately from the opening height. A 2000 mm blade and an opening height of 2000 mm are not the same thing.

Blade width

A size of 600, 700, 800, or 900 mm should not be automatically transferred to the length of the top crossbar. The frame construction and gaps may change the size.

Opening height

Measurement is performed at several points. If the values differ, the problem cannot be solved by randomly trimming DK-001 without understanding the entire installation.

Opening width

It is also checked at the top, middle, and bottom. Wall misalignment affects the mounting gap and the position of the frame.

Wall thickness

DK-001 has a cross-section of 100 × 42 mm. The width of the frame profile and the wall thickness determine whether an extension is needed.

If the wall is wider than the frame, it is useful to study in advance, which extension to buy if the wall is wider than the door frame, and not to discover an uncovered area after installation.

Finished floor level

The posts are calculated relative to the finished floor mark. If the covering is not yet laid, its thickness is taken into account in the project.

Presence of a bottom element

A frame without a threshold and a closed frame have a different number of parts. This choice should appear in the list before cutting.

Connection method

The length of the workpieces and the ends depend on it. The article does not assign a universal type of connection. It is determined by the door design.

Technological allowance

An allowance is needed for cutting, trimming, and adjustment. Its size is agreed with the manufacturer or the craftsman.

Measurement work card

After filling in the table, the customer can move from the general idea to an actual order.

Why DK-001 cannot be called a regular MDF profile

The search phrase "buy MDF door frame" may lead the customer to DK-001, but the product's construction is combined.

The base is made of birch plywood 18 mm thick. The front part consists of two glued layers of MDF, 12 mm each. In total, a cross-section of 100 × 42 mm is formed.

This information is important for three reasons.

The cutting must take into account the profile composition

DK-001 is not a random strip of homogeneous material. The end cutting is performed considering the multilayer structure. The processing method is determined by the craftsman.

The surface is designed for enamel

The front part made of MDF provides a basis for opaque painting. But the expression "under enamel" does not mean a ready white, gray, or any other color.

The following are agreed upon separately:

• shade;

• the priming system;

• gloss level;

• the painting order;

• preparation of ends;

• the finishing of joints;

• the painting of trims and extensions.

The article does not specify specific materials and the number of layers. They are determined by the coating system and the recommendations of the finishing materials manufacturer.

Plywood base does not negate storage precision

A 2400 mm long profile must be received and stored so as to preserve its geometry until cutting. Specific conditions should be clarified with the manufacturer. You cannot leave the profile on site in a random position and expect the finished frame to automatically come out straight.

In the catalog you can buy MDF trim for painting and match DK-001 with platbands, moldings, and other elements of the future opening. At the same time, DK-001 itself should be described precisely: plywood base and MDF face.

3.4 mm groove for the seal: why it is considered before painting

DK-001 provides a 3.4 mm wide groove for the seal. The presence of the groove helps to include the seal in the frame design in advance, but does not mean that any seal fits automatically.

Before ordering, check:

• size of the seal's seating part;

• compatibility with the 3.4 mm groove;

• the required length;

• color;

• installation order;

• effect of coating on groove geometry;

• presence of the seal in a separate specification.

The seal is not specified as automatically included in one DK-001 profile. Its completeness must be verified before payment.

Do not accidentally fill the groove with enamel

When painting, it is important to preserve the seating geometry. A thick coating buildup can change the groove width. The specific protection or cleaning technology is agreed upon with the painter.

When to install the seal

The sequence depends on the finishing system and assembly. A universal answer without a technological map is unreliable. But the final list must include this stage so that the seal is not attempted to be selected after the finished door is installed.

How much seal is needed

The length is calculated based on the actual contour where it is installed. You cannot simply multiply 2400 mm by the number of profiles: part of DK-001 will go to waste, and the seal is required for the finished frame.

The profile, casing, and extension serve different purposes

The buyer often writes in the request "buy a kit for a door opening" and expects that the frame profile will simultaneously cover the wall and the mounting seam. DK-001 forms the frame but does not replace all the trim.

DK-001 forms the frame

The door system is attached and adjoined to the profile according to the project. Its quantity is calculated by posts and crossbars.

The casing covers the installation area

The casing frames the transition between the frame and the wall. Its length, width, and profile are selected separately.

The number of casings cannot be equated to the number of DK-001. The sides of finishing depend on whether the casing is installed on one or both sides of the opening.

The extension widens the frame according to the wall thickness

If the wall is wider than the frame profile, a section remains that needs to be finished. The extension compensates for the difference.

Before ordering, it is useful to study how to buy casings and extensions for a door, and then enter each item into a separate list.

Molding and decorative trim

Additional profiles can support the door style, but they are not automatically included in the frame construction.

In the general category, you can buy trim for an interior door and assemble the frame profile, casings, moldings, and other elements in a unified style.

What to order together with DK-001

The complete doorway basket depends on the project. One DK-001 is not a ready-made frame, and three DK-001s are not a ready-made door.